H(x)=5x^2+40

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Solution for H(x)=5x^2+40 equation: 



(H)=5H^2+40

We move all terms to the left:

(H)-(5H^2+40)=0

We get rid of parentheses

-5H^2+H-40=0

a = -5; b = 1; c = -40;
Δ = b2-4ac
Δ = 12-4·(-5)·(-40)
Δ = -799
Delta is less than zero, so there is no solution for the equation

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